9=-t^2-6t

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Solution for 9=-t^2-6t equation: 



9=-t^2-6t

We move all terms to the left:

9-(-t^2-6t)=0

We get rid of parentheses

t^2+6t+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-6}{2}=-3$

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